tju3275Windy's S(最小表示法)

Xredman posted @ Apr 05, 2010 10:19:44 PM in Algorithm with tags tju 最小表示法 , 1116 阅读

//878303 	2010-04-06 08:54:36	Accepted 	3275	C++ 	0.5K	0'00.13" 	1456K
#include <iostream>
#include <string>
using namespace std;

int main()
{
	int T;
	string S;
	int i, j, k, len;
	cin>>T;
	while(T--)
	{
		cin>>S;
		len = S.length();
		S += S;
		i = 0; j = 1;
		while(i < len && j < len)
		{
			k = 0; 
			while(k < len && S[i + k] == S[j + k])
				k++;
			if(k >= len)
				break;
			if(S[i + k] > S[j + k])
				i= max(i + k + 1, j + 1);
			else
				j = max(i + 1, j + k + 1);
		}
		i = min(i, j);
		for(k = 0; k < len; k++)
			cout<<S[i + k];
		cout<<endl;
	}
	return 0;
}

 

 






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